You can not divide by zeros. You take the limit.

In mathematics, division by zero is division where the divisor (denominator) is zero.

In addition, the 6309 has two possible trap modes, one for an illegal instruction fetch and one for division by zero.

21mn is clearly divisble by 7mn and it's clearly divisible by 3mn, so it's got the mn there it's divisible by 3 it's divisible by 7.

3 is divisible by 3, 24 is divisible by 3 and 48 is divisible by 3.

12 is divisible by 3, so 3 will go into it.

They're both divisible by 5, they're both divisible by r.

This is only divisible by r, that's only divisible by s, that's divisible by neither.

If we're divisible by n 4 we are divisible by n

57, It's not divisible by 2, but it is divisible by 3.

So it's divisible by three natural numbers

20 is definitely divisible by 4, so 120 will be divisible by 4.

Well immediately, both factors are divisible by 3 and both terms are divisible by y.

My second number is seven trillion, twelve billion.

We're divisible by 7m 2n, definitely divisible by 3mn 4.

5 is not divisible by 2, so 2 will not go into 75.

You just add up the digits and if that is divisible by 3, then the number's divisible by 3.

200 is divisible by 8, and then 80 is divisible by 8 as well.

I'm going to be dividing by sixty.

And you divide by n.

So as long as we're divisible by m 2 then we're also going to be divisible by m

7 is not divisible by 3, so 25 will not be divisible by 3.

When you look at them, well these first two are divisible by 4, these last 2 are divisible by 3, but not all of them are divisible any one number.

Zero, zero, zero.

Because you could see 10 goes into the 20, 10 goes into 10.

And, let's see, a u goes into both of these, and a v goes into both of these.

Well, actually, they're both divisible by 4, so maybe you don't realize that they're also both divisible by 8.

So we're going to divide by 4.

25 does go into 103.

So it will be divisible by 3.

Is it divisible by 3?

I'm going to say that it goes into it eight times.

So that is divisible by 3.

I want to divide by 0?

So that is divisible by three.

And finally, divisibility by 10.

Divide the left hand side by 3.

And I sub 3 would look like this 1 0 0, 0 1 0, 0 0 1.

Division

It's definitely not divisible by 12, because 12 goes into 144.

0 minus 0 is 0.

And then the last row is 0, 0, 0.

It has to be divisible by n, and it also has to be divisible by n 4.

So v1, v2, v3 are going to be equal to the 0 vector. 0, 0.

Does 2 go into 1?