least one solution.

We only have one solution.

Only one solution there.

So if the discriminant is equal to 0, you only have one solution.

So it's only going to have one solution.

There's only one particular solution right there.

On one of them, carve Problems are soluble.

Or you could say one real solution or one real root.

There is no one single solution to the problem.

You're only going to have one solution.

And then you are only left with one solution.

So you're only going to have one real solution.

Now, we only got one solution here.

There is only one solution. It's not that hard.

Son, with one signature on one check she can solve all the problems we got.

The Puzzle you entered has only one solution.

You'd have no one solution to this equation.

There's only one solution and it has no alternative.

Let's see if we can do another one.

There is no single solution that can fit all situations.

Or another way to think about it is you only have one solution.

We can only have one solution here, right?

It'll only have one solution to this quadratic in terms of x. But let's simplify it first before we worry about that.

And there's one solution that's probably only a few years off.

You could get one solution is negative 5 2.

You have worked things in such a fashion that we have only one resource left.

One day he'll make a mistake. There's only one answer.

So you could say we only have one solution, or one root, or a repeated root.

So we only have one solution, and by definition it's going to be rational.

One person at a time, one person.

One at a time. One at a time!

So if b squared minus 4ac is equal to 0, you only have one solution.

In the future, we'll see equations where they have more than one solution.

But as you can see from my answer, there's no one size fits all.

So there could be no solution to this, but there has to be at most one solution.

This is equal to our matrix S I'll do it in pink this is equal to our matrix S, which is 1, 0, 0, 1, 1, 0, minus 1, 0, 1, times our matrix A, times 1, minus 1, 1, minus 1, 2, 1, minus 1, 3, 4.

So this first vector right here, this yellow one, 1, 1, 1, it will look like this 1, 1, 1.

One Times One Square....

One, two, one...

So they're going to be 1, minus 1, minus 1.

one real solution, or you could kind of say, you have a repeated root here.

Only somebody from Warburton and Crawley... could have solved that problem.

The score is one all.

One god, One god! One god!

Let's start. 1, 2, 3, Ha!