And I know it's the height because they told me it's a 90 class='bold'>degree class='bold'>angle.

We have a 92 class='bold'>degree class='bold'>angle, we have a 29 class='bold'>degree class='bold'>angle and the other one is 59 class='bold'>degrees.

Locate the base so the ball arm is at a forty five class='bold'>degree (45 ) class='bold'>angle to the T slots

less than 90 class='bold'>degrees you have an acute class='bold'>angle, at 90 class='bold'>degrees you have a right class='bold'>angle,

class='bold'>Angle of 65 class='bold'>degrees.

45 class='bold'>Degrees

45 class='bold'>Degrees

They have 90 class='bold'>degree class='bold'>angle here and they have 90 class='bold'>degree class='bold'>angle there

So we have a 90 class='bold'>degree class='bold'>angle.

I'm going to tell you that this class='bold'>angle here, this big class='bold'>angle here, is 86 class='bold'>degrees.

So the measure of class='bold'>angle DBC would be equal to 90 class='bold'>degrees and we already know that 90 class='bold'>degrees is a special class='bold'>angle, this is a right class='bold'>angle, this is a right class='bold'>angle.

They both have a 90 class='bold'>degree class='bold'>angle.

At the approximate class='bold'>angle of 45 class='bold'>degrees.

This is clearly a right class='bold'>angle, or a 90 class='bold'>degree class='bold'>angle right over here.

And they both have 90 class='bold'>degree class='bold'>angles

The ladder makes a 53 class='bold'>degree class='bold'>angle with the wall.

Take a measurement every 90 class='bold'>degrees of rotation

So anything, this is acute, that is an acute class='bold'>angle, and that is an acute class='bold'>angle right over here. They are less than 90 class='bold'>degrees.

The planes of vibration of the two halteres are orthogonal to each other, each forming an class='bold'>angle of about 45 class='bold'>degrees with the axis of the insect this increases the amount of information gained from the halteres.

It was a right class='bold'>angle, it was a 90 class='bold'>degrees class='bold'>angle

We come down at a 45 class='bold'>degree class='bold'>angle.

So if we see a triclass='bold'>angle that is a 90 class='bold'>degree, 45, and 45 like this,

The other thing that might jump out at you if you take the outer edge of all these class='bold'>angles which are adjacent to each other if you take the outer edge, it forms a straight class='bold'>angle.

And in this case, 14 is opposite the 90 class='bold'>degrees.

Cook at 380 class='bold'>degrees for 45 minutes.

We huddled into that tent, 45 class='bold'>below that day, I'll never forget it.

And these two adjacent class='bold'>angles make up a 90 class='bold'>degree class='bold'>angle so they must add up to 90 class='bold'>degrees.

So each of the interior class='bold'>angles are going to be 120 class='bold'>degrees.

It would have a 90 class='bold'>degree class='bold'>angle, and its slope would be the negative inverse.

The way you draw a 90 class='bold'>degree class='bold'>angle is you draw a little box like that.

In the accompanying diagram, the measure of class='bold'>angle a is 32 class='bold'>degrees.

If two supplementary class='bold'>angles are equal, the class='bold'>angles each measure 90.

(so that's, remember the hypotenuse is opposite the 90 class='bold'>degree side.)

larger than 90 class='bold'>degrees you have an obtuse class='bold'>angle, and if you get all the way to 180 class='bold'>degrees, your class='bold'>angle actually forms a line.

And you can see from our measure right over here that that gives us a 90 class='bold'>degree class='bold'>angle, which is a very interesting class='bold'>angle that shows up many times in geometry and trigonometry, and there's a special word for a 90 class='bold'>degree class='bold'>angle it is called a right class='bold'>angle.

So we know that this whole thing is 90 class='bold'>degrees.

So a right triclass='bold'>angle is a triclass='bold'>angle that has a 90 class='bold'>degree class='bold'>angle in it.

This is, I call it the 30 class='bold'>degree side, it's opposite the 30 class='bold'>degree class='bold'>angle, or it's the shortest side.

The only way that this would be equal to 180, class='bold'>angle 3 plus class='bold'>angle 4, is if class='bold'>angle 4 were a 90 class='bold'>degree class='bold'>angle, and class='bold'>angle 3 were also a 90 class='bold'>degree class='bold'>angle.

Let's say we go up at a 45 class='bold'>degree class='bold'>angle.

So x is 66 class='bold'>degrees now if x is 66 class='bold'>degrees you might find that there is another class='bold'>angle that is not too hard to figure out.

I should get the shortest side, the 30 class='bold'>degree side

I start with the 60 class='bold'>degree side, divided by square root of 3,

A protractor is kinda like a 180 class='bold'>degree class='bold'>Angle A Tron.

The longest side of the right triclass='bold'>angle, or the side that's opposite the 90 class='bold'>degree class='bold'>angle.