These four 1's are just going to be four 1's.

Four of the cards are going to be 1's.

Do You Have The Papers? It's All Right Here.

But then he held it for a little while, Lakshmi.

You'd just have four 1's.

I'll play cards, if you think it'll do any good.

Then the next one is going to be 1 of 35.

You got the high hand now, son, the big cards.

Then the next one is going to be 1 of 34, 33, 32, 31.

Now we know the total number of hands with four 1's is this number.

So they want to know the probability of getting all four of the 1's.

So all four 1's in my hand of 9.

So the number of hands with four 1's is actually just this number.

So number of ways or maybe we should say this number of hands with four 1's.

That's the only combination with four 1's, if we were only picking four cards.

So the numerator in blue is the number of different hands where I have the four 1's and we're dividing the total number of hands.

There's only one way to get that if the remaining cards that's going to give all of the different combinations of having four 1's.

The first card or the first position can be any one of five cards, then four cards, then three cards, then two cards, then one cards.

Well if a hand only had four cards in it, then the number of ways to get a hand with four 1's, there'd only be one way, one combination.

Now a little bit more of a nuanced thought process is, how do we figure out the number of ways in which the event can happen, in which we can have all four 1's.

So for the other five cards if you imagine this slot considering that of the 36 we would have to pick four of them already in order for us to have four 1's.

But we actually want to count how many ways that, if I get a hand of 9 picking from 36, that I can get the four 1's in it.

So about roughly 2 in a thousand chance or 1 in a 500 roughly speaking, this isn't exact odds you have a roughly 1 in 500 chance of getting all four of the 1's in your hand of 9 when you're selecting from 36 unique cards.

So we're left with, the probability of having all four 1's in my hand of 9 that I'm selecting from 36 unique cards is equal to in the numerator, I'm just left with this 2 times 1 times 1 times 1 so it's equal to 2 over 5 times 17 times 11.