You can set y is equal to 0.

You can't set x is equal to 0.

That bit is set to 0 in individual addresses and set to 1 in group addresses.

Let's set y equal to 0.

I just set y is equal to 0 right there, right?

So you set y is equal to 0, and you get 0 is equal to 12x squared minus 5x minus 2.

If we're looking for the solution set to Ax is equal to 0, then that means is equal to the 0 vector, that that means that this sum, we're trying to find a solution set of this sum is equaling 0.

The 0 vector is a member of the set.

We had set it equal to 0.

So you set that equal to 0.

And let's set x5 equal to 0.

If we want to set, if the only place that this can equal to 0 is if this numerator is equal to 0.

So let's set z cubed minus 2z squared is equal to 0.

We start off with this variable sum that is set to 0.

We're going to set that equal to 0.

So let's set x equal 0, so you get 2y plus 1 3, times 0 is equal to 12.

The ordered set A of nonzero real numbers A ( , 0) (0, ) is not a linear continuum.

So we want to figure out where the slope is equal to 0, so this is the slope, so let's set this equal to 0.

And the minimum or maximum point are going to be where this is equal to 0, so let's set that equal to 0.

Now, the one thing that we've done over and over again, we know that the solution set of this equation, the solution set of Rx is equal to 0, is the same as the solution set of Ax is equal to 0.

For the set formula_3, the point 0 is an isolated point.

So let's set this equation as equal to 0.

If we wanted to set this equal to 0, we just say 4x to the third is equal to 0, and we know what x value will make that equal to 0, x has to be equal to 0.

We have a quadratic expression being set equal to 0.

It's the point 0, 0. x is equal to 0 and y is equal to 0.

To do that, we set the function equal to zero, because this is the point y is equal to 0.

Some examples are the set of all integers, ..., 1, 0, 1, 2, ... , is a countably infinite set and the set of all real numbers is an uncountably infinite set.

So I set y equal to 0 and I get this.

Well, 0, plus 1 is sine of 0 is 0 is equal to C.

0 times anything's going to be 0. 0 times anything is going to be 0. 0 times anything's going to be 0.

And we, once again, we're going to have 4 times 0 is 0, 4 times 0 is 0, 4 times 0 is 0, 4 times 1 is 4.

So v1, v2, v3 is equal to 0, 0, 0.

4 times 0 is 0, 4 times 0 is 0, 4 times 0 is 0, 4 times 1 is 4.

If you have a bunch of free variables, you can set all of them but one to equal 0, and then that one that you didn't set to 0, you set it to equal negative 1.

Now, if we're saying that Ax is equal to 0, we're looking for the solution set to that.

So if this is 0, c1 times 0 is going to be equal to 0.

So when x is equal to 0, this 4 times 0 is equal to 0.

0 plus 0 is 0.

0 minus 0 is 0.

0 plus 0 is 0.

0 minus 0 is 0.

0 minus 0 is 0.

So y is 0 and z is 0, so if this is 0 and this is 0, x is going to be equal to 8.

So if it was a thousand times 44, we would get 0 plus 0 is 0, 0 plus 0 is 0, 0 plus 0 is 0, 4 plus 0 is 4, 4 plus nothing is 4.

So this is just going to be equal to 0, 1, 1, 0 minus 1 2 times 0 is 0.